n^2-4/11=0

Solution for n^2-4/11=0 equation:

n^2-4/11=0

We multiply all the terms by the denominator


n^2*11-4=0

Wy multiply elements

11n^2-4=0

a = 11; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·11·(-4)
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{11}}{2*11}=\frac{0-4\sqrt{11}}{22}
=-\frac{4\sqrt{11}}{22}
=-\frac{2\sqrt{11}}{11}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{11}}{2*11}=\frac{0+4\sqrt{11}}{22}
=\frac{4\sqrt{11}}{22}
=\frac{2\sqrt{11}}{11}
$